Optimal. Leaf size=211 \[ \frac{4 \sqrt{2} A \sin (e+f x) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} F_1\left (\frac{1}{2};-\frac{1}{2},-m;\frac{3}{2};\frac{1}{2} (1-\cos (e+f x)),\frac{b (1-\cos (e+f x))}{a+b}\right )}{f \sqrt{\cos (e+f x)+1}}-\frac{4 \sqrt{2} A \sin (e+f x) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} F_1\left (\frac{1}{2};-\frac{3}{2},-m;\frac{3}{2};\frac{1}{2} (1-\cos (e+f x)),\frac{b (1-\cos (e+f x))}{a+b}\right )}{f \sqrt{\cos (e+f x)+1}} \]
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Rubi [A] time = 0.250905, antiderivative size = 211, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192, Rules used = {3018, 2755, 139, 138, 2784} \[ \frac{4 \sqrt{2} A \sin (e+f x) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} F_1\left (\frac{1}{2};-\frac{1}{2},-m;\frac{3}{2};\frac{1}{2} (1-\cos (e+f x)),\frac{b (1-\cos (e+f x))}{a+b}\right )}{f \sqrt{\cos (e+f x)+1}}-\frac{4 \sqrt{2} A \sin (e+f x) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} F_1\left (\frac{1}{2};-\frac{3}{2},-m;\frac{3}{2};\frac{1}{2} (1-\cos (e+f x)),\frac{b (1-\cos (e+f x))}{a+b}\right )}{f \sqrt{\cos (e+f x)+1}} \]
Antiderivative was successfully verified.
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Rule 3018
Rule 2755
Rule 139
Rule 138
Rule 2784
Rubi steps
\begin{align*} \int (a+b \cos (e+f x))^m \left (A-A \cos ^2(e+f x)\right ) \, dx &=-\left (A \int (1+\cos (e+f x))^2 (a+b \cos (e+f x))^m \, dx\right )+(2 A) \int (1+\cos (e+f x)) (a+b \cos (e+f x))^m \, dx\\ &=\frac{(A \sin (e+f x)) \operatorname{Subst}\left (\int \frac{(1+x)^{3/2} (a+b x)^m}{\sqrt{1-x}} \, dx,x,\cos (e+f x)\right )}{f \sqrt{1-\cos (e+f x)} \sqrt{1+\cos (e+f x)}}-\frac{(2 A \sin (e+f x)) \operatorname{Subst}\left (\int \frac{\sqrt{1+x} (a+b x)^m}{\sqrt{1-x}} \, dx,x,\cos (e+f x)\right )}{f \sqrt{1-\cos (e+f x)} \sqrt{1+\cos (e+f x)}}\\ &=\frac{\left (A (a+b \cos (e+f x))^m \left (-\frac{a+b \cos (e+f x)}{-a-b}\right )^{-m} \sin (e+f x)\right ) \operatorname{Subst}\left (\int \frac{(1+x)^{3/2} \left (-\frac{a}{-a-b}-\frac{b x}{-a-b}\right )^m}{\sqrt{1-x}} \, dx,x,\cos (e+f x)\right )}{f \sqrt{1-\cos (e+f x)} \sqrt{1+\cos (e+f x)}}-\frac{\left (2 A (a+b \cos (e+f x))^m \left (-\frac{a+b \cos (e+f x)}{-a-b}\right )^{-m} \sin (e+f x)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+x} \left (-\frac{a}{-a-b}-\frac{b x}{-a-b}\right )^m}{\sqrt{1-x}} \, dx,x,\cos (e+f x)\right )}{f \sqrt{1-\cos (e+f x)} \sqrt{1+\cos (e+f x)}}\\ &=-\frac{4 \sqrt{2} A F_1\left (\frac{1}{2};-\frac{3}{2},-m;\frac{3}{2};\frac{1}{2} (1-\cos (e+f x)),\frac{b (1-\cos (e+f x))}{a+b}\right ) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} \sin (e+f x)}{f \sqrt{1+\cos (e+f x)}}+\frac{4 \sqrt{2} A F_1\left (\frac{1}{2};-\frac{1}{2},-m;\frac{3}{2};\frac{1}{2} (1-\cos (e+f x)),\frac{b (1-\cos (e+f x))}{a+b}\right ) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} \sin (e+f x)}{f \sqrt{1+\cos (e+f x)}}\\ \end{align*}
Mathematica [A] time = 0.338669, size = 119, normalized size = 0.56 \[ \frac{4 A \sin (e+f x) \sqrt{\cos ^2\left (\frac{1}{2} (e+f x)\right )} \tan ^2\left (\frac{1}{2} (e+f x)\right ) (a+b \cos (e+f x))^m \left (\frac{a+b \cos (e+f x)}{a+b}\right )^{-m} F_1\left (\frac{3}{2};-\frac{1}{2},-m;\frac{5}{2};\sin ^2\left (\frac{1}{2} (e+f x)\right ),\frac{2 b \sin ^2\left (\frac{1}{2} (e+f x)\right )}{a+b}\right )}{3 f} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 1.404, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b\cos \left ( fx+e \right ) \right ) ^{m} \left ( A-A \left ( \cos \left ( fx+e \right ) \right ) ^{2} \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\int{\left (A \cos \left (f x + e\right )^{2} - A\right )}{\left (b \cos \left (f x + e\right ) + a\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (A \cos \left (f x + e\right )^{2} - A\right )}{\left (b \cos \left (f x + e\right ) + a\right )}^{m}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -{\left (A \cos \left (f x + e\right )^{2} - A\right )}{\left (b \cos \left (f x + e\right ) + a\right )}^{m}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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